A + B Problem II

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 315214    Accepted Submission(s): 61139

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

 

 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

 

 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

 

 

Sample Input

2

1 2

112233445566778899 998877665544332211

 

 

Sample Output

Case 1: 1 + 2 = 3

Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110

 

 

Author

Ignatius.L

1 #include
      
        2 #include
       
         3 #include
        
          4 using namespace std; 5 int main() { 6     int t,i,k; 7     cin>>t; 8     for(k=1; k<=t; k++) { 9         string a,b,c,m,n;10         int sum,add;11         cin>>a>>b;12         m=a;13         n=b;14         int lena=a.length();15         int lenb=b.length();16         reverse(a.begin(),a.end());//反转字符串 17         reverse(b.begin(),b.end());18         add=0;19         //模拟加法运算 20         for(i=0; i
         
          
           9) {29                 add=1;30                 sum-=10;31             }32             c+=sum+'0';33         }34         if(add)35             c+=add+'0';36         reverse(c.begin(),c.end());//还原 37         cout<<"Case "<
           
            <<":"<